Raj is having a triangular open space in his plot. He divided the land into two parts by drawing
the boundary PQ, where PQ || BC. P is the mid-point of side AB, other measures are given as
Height of triangle is 12 cm, AP=7 cm, BC=10 cm, AC=11 cm. Find 3+3+3=6
A
(i) Length of side PQ
(ii) Length of side AQ
(iii) Length of side PB
Answers
Answered by
2
Height of triangle is 12 cm.
Base BC= 10 cm
Area of AABC = (1/2) base height
= (1/2) BC height
= (1/2)*10*12
= 60 cm²
Area of AABC = 60 cm²
2]Length of side PQ=BC/2 = 10/2 = 5 cm
3)Length of AQ is = AQ=AC/2 11/25.5 cm
4)Length of PB = AP = 7 cm
oyee u r aman21301....wagera wagera?
Answered by
1
Answer:
Height of triangle is 12 cm.
Base BC= 10 cm
Area of AABC = (1/2) base height
= (1/2) BC height
= (1/2)*10*12
= 60 cm²
Area of AABC = 60 cm²
2]Length of side PQ=BC/2 = 10/2 = 5 cm 3)Length of AQ is = AQ=AC/2 11/25.5 cm
4)Length of PB = AP = 7 cm
hope this helps :)
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