Question

Raj's age is 4 times that of Dhiraj, his cousin. 3 years back, Raj was 5 times as old as Dhiraj. What is his present age? 
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Answer 1

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Answer:

Dhiraj's age = x-3 years

Raj's age = 4x-3 years.

That time, Raj's age = 5 times Dhiraj's age

∴ 4x-3 = 5(x-3)

4x-3 = 5x-15

∴ x = 12 years

Let us consider Dhiraj's present age as x years

Raj's present age is 4 times Dhiraj's = 4x years

Dhiraj's age=12 years

Raj's age=12x4=48years

by shagun

Answer 2

Answer:

• The age of Dhiraj is 12 years.
• The age of Raj is 48 years.

★ Given :-

• Raj's age is 4 times that of Dhiraj.
• 3 years back, Raj was 5 times as old as Dhiraj.

★ To Find :-

• Present age

Step-by-step explanation:

Let the age of Dhiraj be x years old.

Therefore, the age of Raj would be 4x years old. (according to given question)

3 years back, the age of Dhiraj would be ( x - 3 ) years old.

And the age of Raj would be ( 4x - 3 ) years old.

According to the given question,

Raj was 5 times as old as Dhiraj 3 years ago.

So the equation would be,

$\sf \: (4x - 3) = 5(x - 3)$

$\sf \implies \: 4x - 3 = 5x - 15$

$\sf \implies \: 5x - 4x = 15 - 3$

$\sf \implies {\boxed{ \red{ \sf x = 12}}}$

$\sf \: Therefore, the \: age \: of \: Dhiraj \: is \: 12 \: years. \:$

$\sf \: And \: the \: age \: of \: Raj \: is \: 4x \: = 48 \: years.$