Math, asked by KLikhi, 3 months ago

Raj's age is 4 times that of Dhiraj, his cousin. 3 years back, Raj was 5 times as old as Dhiraj. What is his present age? 

Answers

Answered by yashmahajan1082003
0

Answer:

48 years And 12 years

Step-by-step explanation:

Let Rajs age be x. and Dhiraj age be y

x=4y....1

x-3=5y-15......2

So,

By 1 and 2,

x=48

y=12

Answered by akadityakapooriscool
0

Answer:

At Present,

Let us consider Dhiraj's present age as x years

As per statement Raj's present age is 4 times of Dhiraj's, therefore his age is 4x years

3 years ago,

Dhiraj's age = x - 3 years

Raj's age = 4x - 3 years.

As per statement, that time, Raj's age was five times of Dhiraj's age

4x - 3 = 5 (x - 3)

4x - 3 = 5x - 15

4x - 5x = - 15 + 3

-x = - 12

x = 12 years

Thus Present age of Dhiraj’s is 12 years and present age of Raj is 4x, means

4 × 12 = 48 years

Answer present age of Raj's is 48 years.

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