Raj tossed 3 dices and there results are noted down then what is the probability that raj gets 10?
Answers
The options for this question are missing:
Following are the options:
a) 1/72
b) 1/9
c) 25/216
d)1/8
In this according to situation there are so many pairs possible
(1,3,6)(1,4,5)(1,5,4)(1,6,3)(2,2,6)(2,3,5)(2,4,4)(2,5,3)(2,6,2)(3,1,6)(3,2,5)(3,3,4)(3,4,3)(3,5,2)(3,6,1)(4,1,5)(4,2,4)(4,3,3)(4,4,2)(4,5,1)(5,1,4)(5,2,3)(5,3,2)(5,4,1)(6,1,3)(6,2,2)(6,3,1)
6*6*6=216
Total pairs =216
Condition pairs=27
So now 27/216=1/8 will be the answer.
Answer:
Step-by-step explanation:
Raj tossed 3 dices
Total outcomes =
Where n is the number of times dice rolled
So, Total outcomes =
Now we are supposed to find the probability that raj gets 10
Favorable outcomes: (1,3,6)(1,4,5)(1,5,4)(1,6,3)(2,2,6)(2,3,5)(2,4,4)(2,5,3)(2,6,2)(3,1,6)(3,2,5)(3,3,4)(3,4,3)(3,5,2)(3,6,1)(4,1,5)(4,2,4)(4,3,3)(4,4,2)(4,5,1)(5,1,4)(5,2,3)(5,3,2)(5,4,1)(6,1,3)(6,2,2)(6,3,1) = 27
Probability that raj gets 10
Hence the probability that raj gets 10 is