Raj wants to get an inverted image of height 5cm of an object kept at a distance of 30 cm from a concave mirror the focal length of the mirror is 10 cm At what distance from the mirror should she place the screen? what will be the type of image and what is the height of image
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Explanation:
1/f=1/u+1/v
1/10-1/30=1/v
3-1/30=1/v
2/30=1/v
v=15cm
hi/ho=-v/h
1/ho=-v/u×hi
1/ho=-15/30×5
ho=-10cm
nature of image is virtual
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