raja has 4 ticket of a lottery for which 12 tickets were sold and 3 prices are to be given .what is the probability that raja will win at least one peice
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Answered by
3
Answer:
as he have 4 tickets and the total no of tickets sold were 12 so we will divide 4/12
= so the anser is 1/3
Answered by
2
Given:
Tickets sold = 12
Tickets with Raja = 4
Tickets whose prices are to be given = 3
To Find:
The probability that raja will win at least one price
Solution:
Let the event where Raja will not win any price = E
Thus,
Number of ways of taking 4 tickets from 9 = n (E)= 9C4
Number of ways of taking 4 tickets from 12 = n(S) 12C4
Probability that Raja will not win any price -
n(E)/n(S)
= 9C4/ 12C4
= (9 × 8 × 7 × 6/ 4 × 3 × 2 × 1) / (12 × 11 × 10 × 9/ 4 × 3 × 2 × 1)
= 14/55
Probability that Raja will at least one price -
= 1 - 14/55
= 55-14/55
= 41/55
Answer: Probability that raja will win at least one price is 41/55
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