Question

Raja is twice as old as Shiyama. Five years ago his age was three times Shyama's age. Find their present age?

Answer 1

Answer:

$Shyama' s \: present \: age \: \\ = 10 \: years \: old \\ Raja 's \: present \: age \: \\ = 20 \: years \: old$

Step-by-step explanation:

$Let \: the \: present \: age \: of \: Shyama \: \\ be \: = x \: years \\ and \: that \: of \: Raja \: be \: = 2x \: years$

$Seven \: years\: before, \\ Shyama \: must \: be = \: (x - 5)years \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: old \\ and \: Raja \: must \: be \: = (2x - 5) \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: years \: old$

$ATQ... \\ Before \: five \: years, \: Raja' s \: age \\ \: was \: 3\: times \: Shyama's \: age = > \\ that \: is \: \: \: \: \: 2x - 5 = 3(x - 5) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2x - 5 = 3x - 15 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 15 - 5 = 3x - 2x \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = 10$

$Therefore \: Raja ' s \: present \: age \\ = > 2x = 2 \times 10 = 20 \: years \\ and \: Shyama' s \: present \: age \\ = > x = 10 \: years \: old$