Math, asked by afsanaparvin630, 9 months ago

Rajan and Rohit had a total of 468 coins in the ratio 11:7. Rajan's mother gave him 14 more coins and Rohit's mother took a few coins from Rohit. Now, the new ratio of coins is 15:8. How many coins does Rohit have?​

Answers

Answered by Shreya44826
49

Answer:

160

Step-by-step explanation:

ratio = 11:7

total coins = 468

let the constant to the ratio be x

11x + 7x = 468

18x = 468

x = 468/18

x = 26

thus rajan had 11x = 286 coins and rohit had 7x = 182 coins

Now,

new ratio = 15:8

now rajan has = 286+14 = 300

let total coins Rohit has now be z

300/z = 15/8

z = 300 * 8 / 15

z = 160

thus rohit has 160 coins

2nd way :

ratio = 11:7

total coins = 468

let the constant to the ratio be x

11x + 7x = 468

18x = 468

x = 468/18

x = 26

thus rajan had 11x = 286 coins and rohit had 7x = 182 coins

Now,

new ratio = 15:8

now rajan has = 286+14 = 300

let coins taken from rohit be x

300 / 182-x = 15/8

300*8 = 15( 182 - x )

24000 = 2730-15x

330 = 15x

x = 22

thus his mother took 22 coins from him

thus total coins he has now = 182 - 22

= 160

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Answered by amoskumarhembram318
1

Step-by-step explanation:

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