Question

Rajan and Sajan are two friends. Find the probability that both have birthday on the same day of an ordinary year. ​

Answer 1

Rajan may have anyone day out of 365 days as birthday, similarly Sajan may have one day out of 365 days as birthday. So total number of ways in which two friends have their birthday is 365 × 365now both may have same birthday on one of the 365 days,so P(both have the same b'day) =365/365×365=1/365.

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