Question

Rajan bought a second hand scooter for Rs.18000 and spent Rs.1600 on its repair. Then he had to

sell it for Rs.17640. Then find the loss percent.​

Answer 1

Answer:

Total cost price for Rajan = Buying price+Amount spent on repair

                                          = 18000 + 1600 = 19600

Selling price = 17640

Loss = 19600-17640 = 1960

Loss % = 1960/19600*100 = 10%

Step-by-step explanation:

Answer 2

Answer

Loss% = 10%

Step-by-step explanation:

Given -:

• CP of the scooter = ₹ 18000
• Money spent on its repair = ₹1600
• SP of the scooter = ₹ 17640

Net CP of the scooter = ₹(18000 + 1600)= ₹19600

Find -:

• Loss percentage

Solution -:

$\star \: \small \rm\bf{Since \: SP < CP , \: Rajan \: as \: a \: loss}$

Hence,

$\small\rm{Loss = (CP - SP)}$

$\small\rm{Loss = ₹(19600 - 17640)}$

$\small\rm \bf {Loss = ₹1960}$

$\small\rm\bf {Loss\% = (\frac{Loss }{CP} \times 100)\% }$

$\small\rm Loss\% = (\frac{1960}{19600} \times 100)\%$

$\small\bf{Loss \% = 10\%}$

$\star \small\bf{NOTE}$

• CP = Cost Price
• SP = Selling Price
• G = Gain
• L = Loss