Rajan celebrated his birthday in an orphanage. He purchased 19x + 26
chocolates. He distributed 10x-13 chocolates there. After coming home he
shared one third of the remaining chocolates with his brother.
(i) How many chocolates did his brother get?
(ii) How many chocolates did he get?
Answers
Step-by-step explanation:
He purchased = 19x+26 chocolates
No.of chocolates he distributed = 10x-13
So, no. of remaining chocolates after distribution = 19x+26 - (10x-13)
= 19x +26 -10x+13 = 9x+39
He gave 1/3 of remaining chocolates to his brother.
(I) No. of chocolates given to his brother
= 1/3 × 9x+39 = 3x+13 chocolates
(ii). No. of chocolates he got
= 9x+39 - ( 3x+13)
= 9x+39-3x-13 = 6x-26 chocolates
Answer:
(i) 3x + 13/3
(ii) 6x + 26/3
Step-by-step explanation:
Total chocolates = 19x + 26
Chocolates distributed in orphanage = 10x - 13
Total chocolates left = (19x + 26) - (10x - 13) = 19x + 26 - 10x + 13
= (19x - 10x) + (26 + 13)
= 9x + 39
Number of chocolates his brother got = 1/3(9x + 39)
= 9x/3 + 39/3 = 3x + 13
Numbers of chocolates left with him = (9x + 13) - (3x + 13)
= 9x + 13 - 3x - 13
= (9x - 3x) + (13 - 13/3) = 6x + (13 - 13)
6x + (13 - 13) = 6x