Math, asked by piyushs, 1 year ago

Rajan got married 8 years ago. His present age is 6/5

times his age at the time of his marriage. Rajan’s sister

was 10 years younger to him at the time of his

marriage. The age of Rajan’s sister is:

A. 32 Years B. 36 Years

C. 38 Years D. 40 Years

Answers

Answered by Aniketpoddar1
26
let his age at the time of his marriage be x
according to question
x+8=6x/5
5x+40=6x
x=40
so his present age =40+8=48
And his sister's age =48-10=38years
Answered by amitnrw
0

The present age of Rajan’s sister is 38 Years

Correct option is C) 38 years

Given:

  • Rajan got married 8 years ago
  • Rajan present age is 6/5 times his age at the time of his marriage
  • Rajan’s sister  10 years younger to him  

To Find:

  • The present age of Rajan’s sister

Solution:

Step 1:

Assume Age of Rajan 8 years before at the time of Marriage = x years

Step 2:

Form an equation according to given data and solve for x

(6/5)x = x + 8

=> x/5 = 8

=> x = 40

Step 3:

Form age of Rajan Sister 8 year before as she was 10 year younger than Rajan

40 - 10 = 30 Years

Step 4:

Form Present age of Rajan Sister by adding 8

30 + 8 = 38 Years

The age of Rajan’s sister is 38 Years

Correct option is C) 38 years

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