Rajani orders three types of sweets for a party. She ordered 4 boxes of
A; 6 boxes of
B and 8 boxes of
C for the party.
If every guest got 4 sweets, how many guests were present at the party?
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4
Answer:
A) Total number of sweets=8×4=32
B) Total number of sweets=6×6= 36
C) Total number of sweets= 4×8=32
Total Number of Sweets as a whole=32+32+36
= 100
Therefore, No of Guests=100÷4 =25 guests.
Answered by
1
Type A contains 8 sweets
she ordered 4 boxes
no. of sweets =8*4=32
Type B contains 6 sweets
she ordered 6 boxes
no. of sweets =6*6=36
Type C contains 4 sweets
she ordered 8 boxes
no. of sweets =4*8=32
Total no. of sweets =32+36+32
100 sweets
Each guest gets 4 sweets
Therefore, no. of guests = 100/4 =25 guests
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