Question

Rajat adds 11.4 g of sugar (C12H2011) (Molecular mass = 342 g/mol) to his coffee. The total number of hydrogen atoms present in his
coffee that had come from the sugar added

Answer 1

Number of Atoms of Hydrogen = 4.956 x 10^34

Explanation:

Let Number of Atoms of Hydrogen = X

No. of. Moles of Sugar = 11.4/342 = 0.034

No. of. Moles of Hydrogen : No of. Moles of Sugar = 22 : 1

(or)

No. of. Moles of Hydrogen = 22 x No. of. Moles of Sugar

No. of. Moles of Hydrogen = 22 x 0.034

No. of. Moles of Hydrogen = 0.748

X = No. of. Moles of Hydrogen x Avogadro's Number

X = 0.748 x (6.626 x 10^34)

X = 4.956 x 10^34

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