rajeev and anuj can do a piece of work in 15 days and 18 days respectively .they work togther for 5 days and then rajeev leaves .in how many days would anuj alone finish the work.
Answers
Answered by
2
Answer:
7 days
Step-by-step explanation:
rajeev one day work =1/15
anuj one day work =1/18
both one day work=1/15+1/18=11/90
work done by both in 5 days=11/90×5=11/18
remaining work=1-11/18=7/18
time anuj will take=7/18÷1/18
=7/18×18
=7 days
Answered by
1
Answer:
Rajeev,swork=1/15
Anuj. .. = 1/18
Combined work=1/15 +1/18
6/90+5/90=15/90=1/6
Comb.work 5 days=1/6x5=5/6
Remains 1-5/6=1/6
Anuj Completes.in1/6x18/1=3 days
Anuj completes in 3 days
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