Math, asked by adreeja7049, 1 year ago

Rajeev's age is four more than the age of Shilpa. The age of Shilpa can be obtained by subtracting four times her age 4 years ago from the four times her age after 4 years. What was Rajeev's age before 4 years ?
A) 36 years
B) 28 years
C) 32 years
D) 40 years

Answers

Answered by Anonymous
0
Let Shilpa's present age is p years

According to question,

p = 4(x+4) – 4(x–4)

p = 4x+16 – 4x+16

p = 32

Shilpa's present age = 32 years

Rajeev is four years older than Shilpa

=> Shilpa's present age = Rajeev's age 4 years before.

=> Rajeev's age 4 years before = 32 years.

Answered by Anonymous
0
Q:

Rajeev's age is four more than the age of Shilpa. The age of Shilpa can be obtained by subtracting four times her age 4 years ago from the four times her age after 4 years. What was Rajeev's age before 4 years ?

A) 36 years
B) 28 years
C) 32 years
D) 40 years

Answer:   C) 32 years 

Read Description:

Let Shilpa's present age is k years

According to question,

k = 4(x+4) – 4(x–4)
k = 4x+16 – 4x+16
k = 32

Shilpa's present age = 32 years

Rajeev is four years older than Shilpa

=> Shilpa's present age = Rajeev's age 4 years before.

=> Rajeev's age 4 years before = 32 years.

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