Rajeev started to move from point A
towards point B exactly an hour after
Rohit
started from B in the opposite directions
but at a speed twice as much as that of
Rohit
By the time Rohit covered one sixth of
the distance between the points B and A.
Rajeev also covered the same distance.
How many hours would Rohit take to
reach A?
6
7
12
2
Answers
Solution :-
Rajeev(A) ------------------------------ Rohit(B)
Let us assume that,
- Total distance from A to B = D km .
- Speed of Rohit = x km/h .
so,
→ Time taken by rohit to cover (1/6) th distance = Distance / speed = (D/6x) hours .
also,
→ Speed of rajiv = 2 * x = 2x km/h .
so,
→ Time taken by rajiv to cover (1/6)th distance = (D/12x) hours .
A/q,
→ (D/6x) - (D/12x) = 1
→ (2D - D)/12x = 1
→ D = 12x .
therefore,
→ Time taken by rohit to reach A = Distance / speed = D/x = 12x/x = 12 hours (C) (Ans.)
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