Question

Rajeev went from Delhi to Chandigarh and return to Delhi on his moterbike.the odometer that read 4200 km at start trip and 4460km at the end of his trip.if Rajeev took 4hr 20 min to complete his trip then find the average speed and average velocity in km/h as well as in m/s

Answer 1

Answer:

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Odometer reading at the start of trip= 4200km

Odometer reading at the end of trip= 4460km

Total distance= 4460-4200

= 260km.

Total time= 4hr 20min or $4 + \frac{1}{3}$

$= \frac{13}{3}$

Therefore,

average speed$= \frac{total \: distance}{total \: time}$

$= \frac{260}{ \frac{13}{3} }$

$= \frac{260}{13} \times 3$

$= 20 \times 3$

$= 60km {h}^{ - 1}$

In m/s

$= 60 \times \frac{5}{18}$

$= 16.66m {s}^{ - 1}$

Average velocity:$\frac{displacement}{time}$

Displacement= 0m

$= \frac{0}{ \frac{13}{3} }$

$= 0m {s}^{</em></strong><strong><em>-</em></strong><strong><em>2}$

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