Rajeev went from Delhi to Chandigarh on his motorbike. The Odometer of bike reads 4200 Km at the start of the trip and 4460 Km at the end of his trip. If Rajeev took 4 hours 20 min to complete his trip, find average speed and average velocity in km/h as well as m/s.
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Answered by
20
Hence the bike traveled 260 km in 4 + 1/3 hour
so the velocity will be 60km/hr. which is 16.6m/s.
so the velocity will be 60km/hr. which is 16.6m/s.
Answered by
35
Distance = 4460Km-4200Km=260Km
time = 4*20/60=4*1/3hours=13/3hours
speed = distance /time =260/13/3=260*3/13=780/13Km/hours=60Km/h
in m/s= 60*1000/60*60=1000/60=16.66...Km/h
If the Rajeev start the trip at home and end his trip in home so the displacement will me zero then velocity In Km/h and m/s will be 0
and if Rajeev start with home and ends in another place so velocity will be like speed
time = 4*20/60=4*1/3hours=13/3hours
speed = distance /time =260/13/3=260*3/13=780/13Km/hours=60Km/h
in m/s= 60*1000/60*60=1000/60=16.66...Km/h
If the Rajeev start the trip at home and end his trip in home so the displacement will me zero then velocity In Km/h and m/s will be 0
and if Rajeev start with home and ends in another place so velocity will be like speed
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