Rajeev went from delhi to chandigarh on his motorbike. the odometer of the bike read 4200 km at the start of trip and 4460 km at the end of his trip. if rajeev took 4 h 20 minutes to complete his trip, find the average speed in km/has well as in m/s
Answers
Answered by
6
4460-4200=260
now the formula of average speed is distance/time
dist is 260 and time is 4h 20 min=4×60+20=260
so,260/260 that is 1km/h
now the formula of average speed is distance/time
dist is 260 and time is 4h 20 min=4×60+20=260
so,260/260 that is 1km/h
vijayakumarpaspuleti:
no you can't do like that
Answered by
9
let,
u=4200 km
v=4460 km
t=4h 20 min so, t= 4h+1/3hr=13/3hr
Therefore,
Average speed = distance/time
d=4460-4200=260km
t= 13/3 hr
That implies,
260/13/3=260/13*3=20*3 = 60kmph
and
1kmph=5/18 m/s
so
60kmph=60*5/18=16.66 m/s
u=4200 km
v=4460 km
t=4h 20 min so, t= 4h+1/3hr=13/3hr
Therefore,
Average speed = distance/time
d=4460-4200=260km
t= 13/3 hr
That implies,
260/13/3=260/13*3=20*3 = 60kmph
and
1kmph=5/18 m/s
so
60kmph=60*5/18=16.66 m/s
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