Math, asked by geetthokchom212, 1 year ago

Rajen sold his car to yaima at a loss of 20%. Yaima spent rs 8400 to repair ang sold the car to gopal for rs 70020 make a profit of 12 1/2. How much did rajesh pay for the car.

Answers

Answered by varunsharma3711
1
⚡Hey mate⚡

✨Here is your answer✨

Rajen sold his car to yaima at a loss of 20 %.

Now yaima spent rupees 8400 to repair and sold the car to gopal for rupees 70020 and make profit 12 1/2.

It means that 70020 is equal to the 112.5% of yaima's coat price

Because 100 % cost price + he makes 12.5 % profit on it.

If 112.5% equal to the 70020 rupees then 1 % equal is

112.5 % = 70020

1 % = 70020 ÷ 112.5

1 % = 622.4

100 % = 62240

Yaima's total cost price is 62240 rupees.

Now how much money yaima pay for car is

Cost price - spent on repair

62240 - 8400 = 53840

Yaima pay 53840 rupees for car to Rajen.

Rajen sold his car to yaima at a loss of 20 %.

It means that total 53840 is 80 % of Rajen cost price

Because 100 % his cost price - 20 % loss so 53840 is equal to the 80 % of the total cost price

80 % = 53840

1 % = 53840 ÷ 80

1 % = 673

100 % = 673 × 100

100 % = 67300

Rajen pay for the car 67300 rupees.

I hope it's helpful for you. Thank you ❤️❤️
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