rajesh cycles 20km from his home to the railway station at a speed of 25 km/h and comes back at the speed of 20km/h. find its average speed
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Answer:
22.22 km/hr =6.17 m/s
Explanation:
average speed is total distance travelled upon total time taken. here, total distance is 20+20 =40km.
as he is going with constant speed that is acceleration is 0. using formula s= ut+ (1/2)(a)(t^2)
as a=0
s=ut. let t1 be time taken from home to station and t2 be the time taken from station to home. therefore, 20= 25(t1) and 20=20(t2)
therefore t1=0.8 and t2= 1
total time taken is t1+t2 = 0.8+1 = 1.8 hr
average speed is 40/1.8
=22.22 km/hr
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