Question

Rajesh das bought two calculators for Rs 1000. He sold one of them at 20% profit and the other at 20% loss.If the selling price of both calculators are same,find the cost price of each calculator.Also,calculate his gain or loss percentin the total transaction.​

Answer 1

Answer:

Pls refer to image attached. You are welcome :) Pls mark as brainliest

Answer 2

Step-by-step explanation:

Rajesh das bought one calculator be x

profit = 20%

another calculator c. p = 1000- x

loss = 20%

Now

case1

s. p = x + 20/100 ×x

= 120x/100

=1.2x ........... 1

case 2

s. p = (1000- x) -20/100(1000- x)

=(10000-10x-2000-2x) /10

= (8000-8x) /10

=800-0.8x........ 2

case 1 = case 2

or, 1.2x=800-0.8x

or, 1.2x + o. 8x=800

or, 2x =800

or x = Rs 400

Rajesh das bought one calculator be x = Rs. 400

another calculator c. p = 1000- x

= 1000- 400 = Rs. 600

Rajesh das bought two calculators c. p=Rs1000

again,

s. p =1.2x

= 1.2 ×400

= Rs 480

Rajesh das sold two calculators = 2×480=960

now,

sp<cp

so,

loss amount = 1000- 960 =Rs.40

loss% = (40/1000) ×100%

= (40/10) %

= 4%

Rajesh das sold two calculators be loss 4%