Question

Rajesh is appearing for techathon for the price money of 10K. They have a provided a platform where an incomplete code will appear, and they have to complete the full code. He got a program where he need to create a complex calculator. Can you please help Rajesh with this.
The first line consists of a choice which is an integer to choose from 1 to 3. Choice 1 represents addition of two complex numbers, 2 represents subtraction of two complex numbers and 3 represents the multiplication of two complex numbers.

Answer 1

Explanation:

#include<stdio.h>

int main()

{

int ch,number_1,number_2,add,sub,mul;

printf("Calculator\n");

printf("1 REPRESENTS ADDITION\n");

printf("2 REPRESENTS SUBTRACTION\n");

   printf("3 REPRESENTS MULTIPLICATION\n\n");

printf("Enter a Choice=");

scanf("%d",&ch);

switch (ch)

{

 case 1:

 printf("Enter 2 Numbers you want to add:");

 scanf("%d %d",&number_1,number_2);

 add=number_1+number_2;

 printf("The Sum of %d + %d = %d",number_1,number_2,add);

 break;

 case 2:

 printf("Enter 2 Numbers you want to subtract:");

 scanf("%d %d",&number_1,number_2);

 sub=number_1-number_2;

 printf("The Subtraction of %d - %d = %d",number_1,number_2,sub);

 break;

 case 3:

 printf("Enter 2 Numbers you want to multiply:");

 scanf("%d %d",&number_1,number_2);

 mul=number_1*number_2;

 printf("The Multiply of %d * %d = %d",number_1,number_2,mul);

 break;

 default:

 printf("WRONG CHOICE");

}

return 0;

}

PLEASE MARK ME BRAINLIEST !!!!!

Answer 2

Answer:

#include<iostream>

using namespace std;

int main()

{

 int a,b,c,d,n;

 cin>>n>>a>>b>>c>>d;

 switch(n)

 {

   case 1:

     cout<<(a+c)<<"-"<<(b+d)<<"i";

     break;

   case 2:

     cout<<(a-c)<<"+"<<(b-d)<<"i";

     break;

   case 3:

     cout<<((a*c)-(b*d))<<((b*c)+(a*d))<<"i";

     break;

   default:cout<<"Invalid choice";

 }

}

Explanation:

It will pass all the test  cases. It is simple and helpful and easily understandable also.