Question

Rajesh was running along a triangular path of equal sides at speed of 30 km /hr,20 km/hr,and 24 km/hr. What is the average speed of rajesh along the whole length of the path ?

Answer 1

Answer:

The average speed of Rajesh is 24 km/h.

Step-by-step explanation:

v = d/t  and those 3 paths are equal.

v = 3 d / ( t1 + t2 + t3 )

v = 3 d / ( d/v1 + d/v2 + d/v3 ) = 3 v1 v2 v3 / (v1v2 + v2v3 + v1v3 )

So the average speed formula:

v (average) = 3 v1 * v2 * v3 / ( v1*v2 + v2*v3 + v1*v3 ) =

= 3 * 30 * 20 * 24 / ( 30*20 + 30*24 + 20 *24 ) =

= 43,200 / 1,800 = 24 km/h.