Math, asked by vijeshkumar2705, 6 months ago

rajis age is three times that of her brother rajan after two years rajis age would be two times that of rajan how old are they now​

Answers

Answered by VishnuPriya2801
64

Answer:-

Let the age of Raji be x years and Rajan be y years.

Given:

Raji is 3 times the age of Rajan.

⟹ Raji's age = 3 * Rajan's age.

⟹ x = 3y -- equation (1)

After 2 years , Raji will be 2 times the age of Rajan.

  • Rajan's age after 2 years = (y + 2) years.

  • Raji's age after 2 years = (x + 2) years.

According to the above condition,

⟹ (x + 2) = 2(y + 2)

Substitute the value of x from equation (1).

⟹ 3y + 2 = 2y + 4

⟹ 3y - 2y = 4 - 2

⟹ y = 2

Substitute the value of y in equation (1).

⟹ x = 3(2)

⟹ x = 6

Therefore,

  • Present age of Raji = x = 6 years.

  • Present age of Rajan = y = 2 years.

Answered by NᴀʏᴀɴSʜƦᴇʏᴀꜱ
37

Given :

  • Raji's age is three times that of her brother rajan after two years raji's age would be two times that of rajan.

 

To find :

  • What are their present ages.

 

According to the question :

  • Let "x and y" be the age of Rajan and Rajis's age.

 

  • Two years later, Rajis's age would be "2x" two times of Rajan.

 

→ (x + 2) 2 = 3x + 2

→ 2x + 4 = 3x + 2

→ 2x - 3x = 4 - 2

x = 2

 

→ y = (x × y)

→ y = (2 × 3)

→ y = 6

 

Therefore,

  • Ranjan's present age = 2 years.
  • Raji's present age = 6 years.
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