Question

rajiv can do a piece of work in 20 days, vinay in 15 days and ravi in 30 days. they all started the work together but rajiv leave after 2 days and vinay leave 3 days before the work is completed. in how may days the work is completed​

Answer 1

Answer:

Raju 1 day work = 1/10

Vicky 1 day work = 1/12

Tinku 1 day work = 1/15

Amount of work done by them(raju+tinku+vicky) in 1 day

= (1/10 + 1/12 + 1/15) = 1/4

Work done by them in 2 day

=2*(1/4) = 1/2

Vicky leaves 3 days before work is completed means remaining 3 day work

is completed by Tinku :

Tinku 3 day work = 3*1/15 = 1/5

Amount of work remaining till now :

= 1 - [(2days work done by them together) + (3 days tinku work)]

= 1-(1/2 + 1/5)

= 3/10

[NOTE : 2DAYS WORK BY THE TOGETHER + 3DAYS TINKU WORK =5DAYS]

[NOTE: NOW WE HAVE TO FINDOUT NUMBEROF DAYS IN WHICH REMAINING WORK IS COMPLETED

BY TINKU AND VICKY]

remaining work = (number of days required) * (tinku + vicky work)

3/10 = X * (1/12 +1/15)

X= 2

TOTAL DAYS = (2days work done by them together) + (3 days tinku work) + (2 days tinku + vicky work)

= 2 + 3 + 2 = 7 ANS