Math, asked by sanka3, 1 year ago

Rajni is seven times as old as his son. After three years, he will be five times his son's age. What is Rajni's present age?​

Answers

Answered by Blaezii
7

Answer:

Son's age now = 5 years

Rajni's age now = 7*5 = 35 years

Step-by-step explanation:

Let son be x years

Rajni = 7x

3 years later

son = x+3 years

dad = 7x +3 years

7x+3=3(x+3)

7x+3=3x+30

7x-3x=30-3

4x =27

x= 5

Son's age now = 5 years

Rajni's age now = 7*5 = 35 years


sanka3: there is no such information of 10 years
Answered by Nehamalik03
12

Answer:

42 years

Step-by-step explanation:

Let's Rajni's present age be R years.

Let his son's present age be S years.

According to the question,

R = 7S

After 3 years,

R + 3 = 5 (S+3)

=> R +3 = 5S + 15

=> R = 5S + 12

Since R = 7S,

7S = 5S + 12

=> 2S = 12

=> S = 6 , R = 42

After 3 years,

S = 9, R = 45

These values satisfy all the conditions.

So, Rajni's present age = 42 years

Similar questions