Question

Raju age is 3 times than of his brother after 2 years his age become 2 times than of his brother whta are their ages now

Answer 1

let raju's brother = x

and raju = x+3

==> after 2 years

so, (x+3+2) = 2 (x+2)

==> x+3+2 = 2x+4

==> x+5 = 2x+4

==> -x = -1 ==> x=1

so, raju brother = 1

and raju = x+3 = 1+3 == 4

Answer 2

Let the current age of raju is x years and of his brother y years

According to question

x=3y.................(1)

After 2 years Raju age will be x+2 and of his brother y+2 then

x+2=2(y+2)..................(2)

Put the value of x in equation 2 we get

3y+2=2(y+2)

3y+2=2y+4

y=2

put the value of y in (1) we get x=6

Hence Current age of Raju is 6 years and of his brother 2 years.