Question

Raju and Rajender together have 45 marbels. Both of them lost 5 marbels each and the product of
the number of marbels now they have is 124. Represent the situation in the form of quadratic
equation.​

Answer 1

Answer:

Given John and jivanti together have 45 marbles

Let the number of Marbles John had be= x

Then the number of marbles jivanti had= 45-x

Both of them lost 5 Marbles each

Therefore, the number of marbles John had= x-5

The number of marbles jivanti had= 45-x-5= 40-x

Now product of the number of Marbles =124

Therefore , (x-5)(40-x)=124

40- x²-200+5x=124

-x²+45x-200-124=0

x² -45x+324=0. (Multiplying by(-1))

By factorisation method

x²-36x-9x+324=0

x(x-36) - 9(x-36)=0

(x-36)(x-9)=0

x=36 or x= 9

When John has 36 Marbles and jivanti has = 45-x= 45-36=9 marbles

When John has 9 Marbles and jivanti has= 45-x= 45- 9= 36 marbles

PLZ MARK AS BRIANLIEST AND THX FOR THE SUPERB QUESTION

Answer 2

Answer:

Let Marbles with Raju = x and marbles with Rajendra = 45-x

So,

(x-5)(45-x-5)= 124

=> (x-5)(40-x) = 124