Raju can do a piece of work in 10 days, Vicky in 12 days and Tinku in 15 days. They all start the work together, but Raju leaves after 2 days and Vicky leaves 3 days before the work is completed. In how many days is the work completed?
Answers
Answer:
7 days
Step-by-step explanation:
Raju can do the work in 10 days
1 day = 1/10 of the work
Vicky can do the work in 12 days
1 day = 1/12 of the work
Tinku can do the the work in 15 days
1 day = 1/15 of the work
Find the amount of work done in the first 2 days:
1 day = 1/10 + 1/12 + 1/15 = 1/4
2 days = 1/4 x 2 = 1/2 of the work
Find the amount of work Tinku did in the last 3 days alone
1 day = 1/15 of the work
3 days = 1/15 x 3 = 1/5 of the work
Find the amount of work Vicky and Tinku did together:
Amount of work = 1 - 1/2 - 1/5 = 3/10
Find the amount time they take to finish the work:
1 day = 1/12 + 1/15 = 3/20
Number of days needed = 3/10 ÷ 3/20 = 2 days
Find the total number of days needed to complete the work:
Number of days = 2 + 2 + 3 = 7 days
Answer: 7 days
Answer:
Step-by-step explanation:
Work done by Raju in 1 day=>1/10
Work done by Vicky in 1 day=>1/12
Work done by Tinku in 1 day=>1/15
Initialy 3 of them work together for 2 days...
One of them leaves after that working for X days...
at last only Tinku remains n works for 3 days...
So
2*(1/10+1/12+1/15) + X*(1/12+1/15) + 3*(1/15)=1
Solving :x=2
Hence 2+2+3=7.
Total work was done in 7 days.