Question

raju completes a work in 7/6 hours , whereas radha completes the same work in 5/3 hours who completes the work earlier and by how much​

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

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Answer 2

Answer:

Time to finish a work by Raju = \frac{5}{6}

6

5

hours

Time to finish the work by Vrinda = \frac{3}{4}

4

3

hours

To Find :

which fraction of time is longer and by how much?

Solution :

To find the bigger fraction we will equate the denominators of the fractions first.

\frac{5}{6}=\frac{5\times 4}{6\times 4}

6

5

=

6×4

5×4

= \frac{20}{24}

24

20

Similarly,

\frac{3}{4}=\frac{3\times 6}{4\times 6}

4

3

=

4×6

3×6

= \frac{18}{24}

24

18

Now by comparing numerators of both the new fractions we find that \frac{5}{6}

6

5

is bigger.

Therefore, time taken by Raju is longer.

Difference in time to finish the work = \frac{5}{6}-\frac{3}{4}

6

5

−

4

3

= \frac{10-9}{12}

12

10−9

= \frac{1}{12}

12

1

Raju takes \frac{1}{12}

12

1

hours more than Vrinda.

Step-by-step explanation:

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