Question

Raju did some preliminary experiment with the lenses and found that the magnification of the eyepiece (L2 ) is 3.If in his experiment with L2 he found the image at 24 cm from the lens, at what distance did he put the object? *​

Answer 1

Step-by-step explanation:

Given Raju did some preliminary experiment with the lenses and found that the magnification of the eyepiece (L2 ) is 3.If in his experiment with L2 he found the image at 24 cm from the lens, at what distance did he put the object?

• So we have two types of lenses. One is the lens and the other is magnification of the eyepiece and so it is 3. So the eye piece is convex lens. So magnification is given by
•        So height of image / height of object = image distance / object  distance
•                                                      So hi / ho = v/u          
•                                                                         = 3
• According to the question, an experiment with L2 the image is at 24 cm from the lens. So we need to find the distance the object has been put.
• So we have    24 / u = 3
•                Or 3 u = 24
•                Or u = 24 / 3
•               Or u = 8 cm

Reference link will be

https://brainly.in/question/25506124

Answer 2

Answer:

U=8cmwill be the correct Answer hope it helps you