Raju distributes 91 amongst three brothers in such a way that the eldest gets twice as much as the youngest and 11 times as much as the middle brother. Find the share of the eldest brother.
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Given: ₹91 is to be distributed among three brothers such that eldest gets twice than
the youngest and eleven times as much as youngest
To find: Share of the eldest brother
Solution: Let the share of eldest brother be x.
Share of youngest brother=x/2
Share of middle brother=x/11
According to question,
x+x/2+x/11=91
=>(22x+11x+2x)/22=91
=>35x= 91*22
=>x= 57.2
Therefore, the eldest brother gets ₹57.2.
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