Math, asked by sreenikethvinod9613, 1 year ago

Raju fathers age is 3 times of his son age. After 8 years his father age will be 2 1/2 years of his sons age . After 8 more years his father age how many times more than that of his sons age?

Answers

Answered by sindhug1612
1
Raju=x
Father=3x
After 8 years:
Raju's age=x+8
Father's age=3x+8
Given that,
3x+8=5/2(x+8)
6x+16=5x+40
X=24
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