Question

Raju has seen that his uncle is working on computer,
he imitates the shape from computer on a graph paper.
Answer the following questions below.

1 Name the shape Raju's uncle drawn.
a) Spiral
b) Ellipse
c) Linear
Parabola
2 Degree of quadratic polynomial is
a) 3
b) 4
c) 2
d) 1
35 is an example of
a) Zero polynomial b) constant polynomial c) linear polynomial d)
variable
4 The shape drawn on graph may represent
a) -X-2
b) y = - X+2
c) y= x2 – X-2
5 The number of zeroes of the polynomial (shape drawn)
a) 2
b) 3
c) 4
d) 0
​

Answer 1

SOLUTION

TO DETERMINE

Raju has seen that his uncle is working on computer,

he imitates the shape from computer on a graph Paper. Answer the following questions below.

1. Name the shape Raju's uncle drawn.

a) Spiral

b) Ellipse

c) Linear

d) Parabola

2. Degree of quadratic polynomial is

a) 3

b) 4

c) 2

d) 1

3. 5 is an example of

a) Zero polynomial

b) constant polynomial

c) linear polynomial

d) variable

4. The shape drawn on graph may represent

a) y = - x - 2

b) y = - x + 2

c) y= x² - x - 2

5. The number of zeroes of the polynomial (shape drawn)

a) 2

b) 3

c) 4

d) 0

EVALUATION

1. The shape Raju's uncle drawn

d) Parabola

2. A quadratic polynomial is polynomial where the highest power of its variable that appears with nonzero coefficient is 2

Hence Degree of quadratic polynomial is

c) 2

3. 5 can be rewritten as

$\sf{5 = 5 \times {x}^{0} }$

We see that the highest power of its variable that appears with nonzero coefficient is 0

Hence 5 is an example of

a) Zero polynomial

4. From the figure we see that the graph cuts X axis at - 1 and 2

So the required Quadratic polynomial is

$\sf{y = {x}^{2} - ( - 1 + 2)x + ( - 1 \times 2)}$

$\sf{ \implies \: y = {x}^{2} - x - 2}$

Hence the shape drawn on graph may represent

c) y = x² - x - 2

5. From the figure we see that the graph cuts X axis at - 1 and 2

So number of zeroes of the polynomial = 2

Hence the number of zeroes of the polynomial (shape drawn)

a) 2

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Answer 2

Answer:

Step-by-step explanation: