Math, asked by tenz, 1 year ago

raju is 19 years younger than his cousin. after 5 years, their ages will be in the ratio 2:3. find their present ages.


tenz: plss show me the solutions
shriyasri: Don't u think the question is a bit different
tenz: no
tenz: i wrote the book question

Answers

Answered by Anonymous
116
COUSIN'S AGE  = x

RAJU'S AGE = x - 19

AFTER 5 YRS., RATIO = 2/3

SO, (x - 19) + 5 / x + 5 = 2/3

x - 14 / x +5 = 2/3

3x - 42 = 2x + 10 (CROSS MULTIPLICATION)

SO, WE GET x = 52 SO, COUSIN'S AGE = 52 AND RAJU'S AGE = 52 - 19 = 33

hope it helps u out!!!
Answered by Anonymous
6

Ⓖⓘⓥⓔⓝ :-

Raju is 19 years younger than his cousin.

ratios of their ages after 5 years = 2:3

Ⓕⓘⓝⓓ :-

THEIR PRESENT AGES ?

Ⓢⓞⓛⓤⓣⓘⓞⓝ  :-

Let age of cousin be x years

\therefore Age of Raju = x-19 years

After 5 years

Age of cousin = x+5 years

Age of Raju = x - 19 + 5 = x - 14 years

ACCORDING TO QUESTION

 \frac{x - 14}{x + 5}  =  \frac{2}{3}

 = 3 \times ( x - 14) = 2( x+ 5)

 =  > 3x - 42 = 2x + 10

collect \: like \: terms

 =  > 3x - 2x = 10 + 42

x = 52

So, Present age of:

cousin = x = 52 years

Raju = x -19 = 52 - 19 = 33 years

so, \: cousin \: present \: age \underline{ \boxed{52 \: years}}

and \: Raju\: present \: age \underline{ \boxed{33 \: years}}

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