Math, asked by 5ballonders, 8 months ago

- Raju is 19 years younger than his cousin. After 5 years, their ages will be in the ratio 2:3.
Find their present ages.​

Answers

Answered by paramjit85
4

Step-by-step explanation:

Raju is 19 years younger than his cousin.

ratios of their ages after 5 years = 2:3

Ⓕⓘⓝⓓ :-

THEIR PRESENT AGES ?

Ⓢⓞⓛⓤⓣⓘⓞⓝ  :-

Let age of cousin be x years

\therefore∴ Age of Raju = x-19 years

After 5 years

Age of cousin = x+5 years

Age of Raju = x - 19 + 5 = x - 14 years

ACCORDING TO QUESTION

\frac{x - 14}{x + 5} = \frac{2}{3}

x+5

x−14

= 23

= 3 \times ( x - 14) = 2( x+ 5)=3×(x−14)=2(x+5)

= > 3x - 42 = 2x + 10=>3x−42=2x+10

collect \: like \: termscollectliketerms

= > 3x - 2x = 10 + 42=>3x−2x=10+42

x = 52x=52

So, Present age of:

cousin = x = 52 years

Raju = x -19 = 52 - 19 = 33 years

so, \: cousin \: present \: age \underline{ \boxed{52 \: years}}so,cousinpresentage

52years

and \: Raju\: present \: age \underline{ \boxed{33 \: years}}andRajupresentage

33years

Answered by RonitHelper5678
0

Answer:

After 5 years their ages will be x + 5 and x + 24 respectively

According to question the equation so formed is

(x+5)/(x+24)=2/3

=>3(x+5)=2(x+24)

=> 3 x+ 15 = 2 x + 48

=> 3x - 2 x = 48 - 15

=> x= 33

Therefore Raju's age is 33 or Raju is 33 years old

and his cousin's 8 = x + 19

= 33 + 19 = 52

therefore his cousin is 52 years old

Hope it helps please mark as brainliest

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