Question

Raju is 19 years younget than his cousin.After 5 years there ages will be in the ratio 2:3.find there present ages

Answer 1

Let Raju's age be x years
Cousin's age=x+19 years.
ATQ
x/x+19=2/3
3x=2(x+19)
3x=2x+38
x=38
So Raju's age=38 years
Cousin's age =38+19=57 years
HOPE IT HELPS!!!!

Answer 2

GIVEN:-

Raju is 19 years younger than his Cousin.

ratios of their ages after 5 years = 2:3

FIND:-

THEIR PRESENT AGES ?

SOLUTION:-

Let age of Cousin be x years

$\therefore$ Age of Raju = x-19 years

After 5 years

Age of Cousin = x+5 years

Age of Ram = x - 19 + 5 = x - 14 years

ACCORDING TO QUESTION

$\frac{x - 14}{x + 5} = \frac{2}{3}$

$= 3 \times ( x - 14) = 2( x+ 5)$

$= > 3x - 42 = 2x + 10$

$collect \: like \: terms$

$= > 3x - 2x = 10 + 42$

$x = 52$

So, Present age of:

COUSIN = x = 52 years

Raju = x -19 = 52 - 19 = 33 years

$so, \: Cousin \: present \: age \underline{ \boxed{52 \: years}}$

$and \: Raju\: present \: age \underline{ \boxed{33 \: years}}$