Raju is
twice as
his cousin.
After 5 years their
ages will be in the ratio 2:3. find
their present
present ages.
Answers
Answered by
1
Answer:
5
Step-by-step explanation:
Raju's Cousin age = x(let)
Raju age = 2x
After 5 years
Raju' cousin age = x + 5
Raju Age = 2x+5
Therefore , (x+5)/(2x+5)=2/3
=> 3(x+5) = 2(2x+5)
=> 3x+15 = 4x + 10
=> 3x-4x = 10 - 15
=> -x = -5
=> x = 5
Answered by
10
Given :
- Raju is twice as his cousin and after 5 years their ages will be in the ratio 2 : 3.
To Find :
- Their present ages.
Solution :
Let
- Present age of Raju's cousin = x years
- Present age of Raju = 2x years
After 5 years
- Raju's cousin's age = (x + 5) years
- Raju's age = (2x + 5) years
It is given that
- After 5 years, their ages will be in the ratio 2 : 3.
According to question :
→ x + 5/2x + 5 = 2/3
→ 3 (x + 5) = 2 (2x + 5)
→ 3x + 15 = 4x + 10
→ 4x - 3x = 15 - 10
→ x = 5
Hence,
- Raju's cousin's present age = x => 5 years
- Raju's present age = 2x => 10 years
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