Math, asked by prakriti192, 4 months ago

Raju is
twice as
his cousin.
After 5 years their
ages will be in the ratio 2:3. find
their present
present ages.​

Answers

Answered by harshkhetan
1

Answer:

5

Step-by-step explanation:

Raju's Cousin age = x(let)

Raju age = 2x

After 5 years

Raju' cousin age = x + 5

Raju Age = 2x+5

Therefore , (x+5)/(2x+5)=2/3

    => 3(x+5) = 2(2x+5)

    => 3x+15 = 4x + 10

    => 3x-4x =  10 - 15

    => -x = -5

    => x  = 5

Answered by Anonymous
10

Given :

  • Raju is twice as his cousin and after 5 years their ages will be in the ratio 2 : 3.

To Find :

  • Their present ages.

Solution :

Let

  • Present age of Raju's cousin = x years
  • Present age of Raju = 2x years

After 5 years

  • Raju's cousin's age = (x + 5) years
  • Raju's age = (2x + 5) years

It is given that

  • After 5 years, their ages will be in the ratio 2 : 3.

According to question :

→ x + 5/2x + 5 = 2/3

→ 3 (x + 5) = 2 (2x + 5)

→ 3x + 15 = 4x + 10

→ 4x - 3x = 15 - 10

→ x = 5

Hence,

  • Raju's cousin's present age = x => 5 years
  • Raju's present age = 2x => 10 years
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