Raju is twice year old as his son and their sum is 50 find their present ages
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son=x ,Raju x+2x=3x
4x=50 ,x=12.5 ,son= 12.5 , Raju= 37.5.
4x=50 ,x=12.5 ,son= 12.5 , Raju= 37.5.
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raju's son age=x
his age=2x
present age =x+2x=50
3x=50
x=50/3
2x=2×50/3
his age=2x
present age =x+2x=50
3x=50
x=50/3
2x=2×50/3
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