Question

Raju's brother's is twice Raju's age. After 5 years his age is 5/3 times Raju's age.
Find their present ages.​

Answer 1

Answer:

let raju' present age be x

Raju's brother's present age 2x

Raju's age after 5 years x + 5

Raju's brother's she after 5 years 2x + 5

it is given that after 5 years, raju's

brothers age will be 5/3 times raju's

age

=> (2x + 5) = 5/3 * (x + 5)

=> 2x + 5 = (5x + 25)/3

=> 6x + 15 = 5x + 25 [ by cross multiplication ]

=> 6x - 5x = 25 - 15

=> x = 10

then Raju's age is 10 years

Raju's brother's age is 20 years

Answer 2

Answer:

10 years and 20 years

Step-by-step explanation:

Let Raju's age be a years, then his brother's age is 2a years.

After 5 years his age is 5/3 times Raju's age.

2a+5=5/3(a+5)

2a+5=(5a+25)

3

3(2a+5)=5a+25

6a+15=5a+25

6a-5a=25-15

a=10

Therefore, Raju's age is 10 years

Raju's brother's age is 20 years

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