Question

Raju's father is 25 years older than Raju. Ten years later, the father's age is twice the son's age.​

Answer 1

Appropriate question:

• Raju's father is 25 years older than Raju. Ten years later, the father's age is twice the son's age, find their present ages.

Given:

• Raju's father is 25 years older than Raju.
• After 10 years, the father's age will be twice the son's age.

To find:

• Their present ages.

Solution:

❐ Let Raju's age be x years and according to the given question his father's age be (x + 25) years.

After 10 years, their ages,

• Raju's age = (x + 10) years
• Father's age = (x + 25 + 10) years

ATQ,

• After 10 years, the father's age is twice the son's age, therefore,

⇒ 2(x + 10) = (x + 25 + 10)

⇒ 2x + 20 = x + 35

⇒ 2x - x = 35 - 20

⇒ x = 15

Hence,

• Present age of Raju = x = 15 years
• Present age of father = (x + 25) = (15 + 25) = 40 years

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Answer 2

Appropriate question:

Raju's father is 25 years older than Raju. Ten years later, the father's age is twice the son's age, find their present ages.

Given:

Raju's father is 25 years older than Raju.

After 10 years, the father's age will be twice the son's age.

To find:

Their present ages.

Solution:

❐ Let Raju's age be x years and according to the given question his father's age be (x + 25) years.

After 10 years, their ages,

Raju's age = (x + 10) years

Father's age = (x + 25 + 10) years

ATQ,

After 10 years, the father's age is twice the son's age, therefore,

⇒ 2(x + 10) = (x + 25 + 10)

⇒ 2x + 20 = x + 35

⇒ 2x - x = 35 - 20

⇒ x = 15

Hence,

Present age of Raju = x = 15 years

Present age of father = (x + 25) = (15 + 25) = 40 years

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ANSWER