Math, asked by eduurmila36, 9 months ago

Raju said an algebraic expressions which contains only constant term is not a polynomial are you support rajus statement ? explain

Answers

Answered by Swarup1998
2

Statement given by Raju was incorrect.

Step-by-step explanation:

Let us look at the definition of a polynomial first.

An expression of the form

a₀ xⁿ + a₁ xⁿ⁻¹ + a₂ xⁿ⁻² + ... + aₙ_₁ x + aₙ,

where a₀, a₁, a₂, ..., aₙ are given (real or complex), n is a non-negative integer and x is variable, is called a polynomial in x.

Now to define the statement "algebraic expression containing constant term only", we take

a₀ = a₁ = a₂ = ... = aₙ_₁ = 0

and we get the expression

f(x) = constant

∴ using the above definition, we can conclude that f(x) is a polynomial of degree 0.

Polynomial problems:

1. How to multiply a polynomial by a polynomial?

- https://brainly.in/question/7485362

2. How many zeros are there in linear polynomial, quadratic polynomial and in cubic polynomial?

- https://brainly.in/question/1358551

Answered by slicergiza
2

Answer:

No, he is not correct.

Step-by-step explanation:

A polynomial is an expression consisting of variables and coefficients,

That written in the form of,

f(x)=a_nx^{n}+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+........+a_0

Where,

n = a whole number,

And,

a_n, a_{n-1}.....a_0\text{ are constant terms}

If n = 0,

f(x)=a_0

Thus, an algebraic expressions which contains only constant term is always a polynomial with degree ( highest power of its monomial or single term ) 0.

Hence, Raju is INCORRECT.

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