Question

Raju saves money Rs 501st month increase savings Rs100 in successive month how much amount with him after 1year

Answer 1

Answer:

Clearly saving of Yasmeen forms an AP with first term a=32 and common difference d=36−32=4.

Let it take n months to saves Rs. 2000.

∴S

n

=

2

n

[2a+(n−1)d]=2000

⇒

2

n

[2×32+(n−1)×4]=2000

⇒n[2n+30]=2000

⇒n[n+15]=1000

⇒n

2

+15n−1000=0

⇒(n+40)(n−25)=0

⇒n=−40,25

But n=-40 being negative integer is not possible.

∴n=25

Hence, it takes 25 months for Yasmeen to saves Rs.2000.

Answer 2

Answer:

1601 because 501+100*11