Math, asked by tonyjalem, 8 months ago

Raju sells two apartments for equal price each. On one transaction he loses 40% and the other he gains
40%. What is his net profit or loss percentage?​

Answers

Answered by Arrush
7

Answer:

Loss; 16 %

Step-by-step explanation:

Let the selling price be SP each

1st Transaction:

Selling Price: SP

Loss: 40 %

Cost Price: CP_{1\\\\}

So,

    \frac{CP_{1}- SP}{CP_{1} } = 40%

    \frac{CP_{1}- SP}{CP_{1} } = \frac{40}{100}

    CP_{1} - SP = 0.4*CP_{1}

    0.6*CP_{1}\\ = SP

    CP_{1} = \frac{5SP}{3}

   

2nd Transaction:

Selling Price: SP

Profit: 40%

Cost Price: CP_{2\\}

So,

    \frac{SP - CP_{2\\}}{CP_{2\\}} = 40%

     \frac{SP - CP_{2\\}}{CP_{2\\}} = \frac{40}{100}

    SP - CP_{2} = 0.4*CP_{2}

    SP = 1.4*CP_{2}

    CP_{2} = \frac{5SP}{7}

Now,

Total Selling Price = 2SP

Total Cost Price = \frac{5SP}{3} + \frac{5SP}{7}

                          = \frac{35SP + 15SP}{21}

                          = \frac{50SP}{21}

                          = 2.38 SP

As, Cost Price is greater than Selling Price

∴ there is a loss

Loss percentage = (Total cost price - Total selling price) / cost price * 100 %

= \frac{ \frac{50SP}{21}  - 2SP}{\frac{50SP}{21}} * 100 %

= \frac{8SP}{50SP} * 100 %

= 16 %

This took a lot of time ^-^ Hope this helps!!

Similar questions