Raju takes 4 hours more than to cover a distance of 40 kilometre if Raju Doubles his speed Ajay he takes 1/2 hours more than Ajay to cover the same distance. Find the speed of Raju and Ajay.
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Answer:
Speed of Raju is 5.7 km/hr and Speed of Ajay is 13.3 km/hr.
Step-by-step explanation:
let the speed of Raju = x km/hr
the speed of Ajay = y km/hr
According to the question,
40/x - 40/y = 4 ..........................(1)
40/2x - 40/y = 1/2 ......................(2)
put 1/x = u and 1/y = v in (1) & (2)
we get
40u - 40 v = 4
20u - 40v = 1/2
40u - 40v = 4 ........................(3)
40u - 80v = 1 ..........................(4)
Subtract (4) from (3),
-40v - ( -80v ) = 4 - 1
-40v + 80v = 3
40v = 3
v = 3/40
put this in (3), we get
40u - 40(3/40) = 4
40u - 3 = 4
40u = 7
u = 7/40
Now, 1/x = u ⇒ 1/x = 7/40 ⇒ x = 40/7 = 5.7
1/y = v ⇒ 1/y = 3/40 ⇒ y = 40/3 = 13.3
Therefore, Speed of Raju is 5.7 km/hr and Speed of Ajay is 13.3 km/hr.
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