Question

Raju walked 2m towards east, took a right turn and walked 7m. He, then took a left turn and walked 5m before taking a left turn and walking 7m. He, then took a final right turn and walked 1m before stopping. How far is raju from the starting point?

Answer 1

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Answer 2

Appropriate Question

Raju started from a point and walked 30m West in 5min.Then he turned south and covered 40m in 3min caluclate Raju's average velocity.

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Answer

Given

Let the Raju's starting point be A.

Let Raju's Final point be c.

• The figure in the attachment shows Raju's journey.

• The dashed line in the colour red indicates Raju's displacement.

To Find

Raju's average speed.

Raju's average velocity.

Formula to be used

• Average Speed = $\sf{ \frac{Total \: distance \: covered \: }{Total \: time \: taken \: }}$

• Average velocity = $\sf{ \frac{Total \: displacement \: }{Total \: time \: taken \: }}$

Solution

To caluclate average speed :

Total distance covered by Raju AB + BC = 30 m + 40 m = 70 m

To caluclate average velocity :

Raju's displacement from A to C is AC.

Since,A ABC is right - angled triangle.

We can Apply the pythagoras theorem to caluclate the length of AC.AB² + BC² = AC².

30² + 40² = AC²

AC² = 900 + 1600 = 2500

AC = 50m

Average velocity = $\sf{ \frac{Total \: displacement \: }{Total \: time \: taken \: }}$

Average velocity = $\sf{ \frac{50m}{480s }}$ = 0.104 m/s

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Required Answer

• Raju's average speed is 0.146 m/s

• Raju's average velocity is 0.104 m/s directed from A to C.

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