Question

rakesh runs at 5/4 of his usual speed and reaches the playground 5 min earlier . What is his usual time.. plzz help me and post the correct answer..

Answer 1

Let Rakesh's initial speed = x
then his final speed = 5x/4 ( because he is running at 5/4 of his usual speed )
initial speed : final speed = x : 5x/4 = 4 : 5 and then his time ratio = 5x/4 : x
He reached 5 min earlier so his new time minus initial time = 5x/4 - x = x/4
and x/4 = 5
so his new time will be 20 minutes and then his usual time will be 25 minutes ( because he reached 5 min earlier as given in the question so ans is 20 min + 5 min = 25 min )

Answer 2

Answer:

Step-by-step explanation:

Let Rakesh's initial speed = x

then his final speed = 5x/4 ( because he is running at 5/4 of his usual speed )

initial speed : final speed = x : 5x/4 = 4 : 5 and then his time ratio = 5x/4 : x

He reached 5 min earlier so his new time minus initial time = 5x/4 - x = x/4

and x/4 = 5

so his new time will be 20 minutes and then his usual time will be 25 minutes ( because he reached 5 min earlier as given in the question so ans is 20 min + 5 min = 25 min )