Question

Rakesh runs at 5/4 of his usual speed and reaches the playground 5 minutes eatlier . what is his usual time ?​

Answer 1

$\huge \fbox \colorbox{aquamarine}{heya }:$

⭐question:

Rakesh runs at 5/4 of his usual speed and reaches the playground 5 minutes eatlier . what is his usual time ?

⭐answer:

let the usual speed of rakesh be = x

distance of school be = y

$\frac{y}{x \times 4by5} - \frac{y}{x} = \frac{1}{15}$

$\frac{5y}{4x} - \frac{y}{x} = \frac{1}{15}$

$\frac{y}{4x} = \frac{1}{15}$

$\frac{y}{x} = \frac{4}{15} = 16$

hence the required answer is

16 minutes.

⭐at end:

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